Answer:
[tex](3+xz)(-3+xz)[/tex]
[tex](y^2-xy)(y^2+xy)[/tex]
Step-by-step explanation:
The Difference of Squares
Any difference of two squared monomial results in a factored form like shown below:
[tex]a^2-b^2=(a-b)(a+b)[/tex]
Similarly:
[tex](a-b)(a+b)=a^2-b^2[/tex]
For a product of binomials to be a difference of squares, they must be in the described form.
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(x-y)(y-x) can be rewritten as:
-(x-y)(x-y)
Since both binomials are identicals, the product will not result in a difference of squares.
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(6-y)(6-Y)
Since both binomials are identicals, the product will not result in a difference of squares.
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(3+xz)(-3+xz) can be rewritten as:
(xz+3)(xz-3). This product is a sum multiplied by a difference of the very same terms, thus the result is a difference of squares:
[tex](3+xz)(-3+xz)=(xz)^2-9[/tex]
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[tex](y^2-xy)(y^2+xy)[/tex]. This product is a sum multiplied by a difference of the very same terms, thus the result is a difference of squares:
[tex](y^2-xy)(y^2+xy)=y^4-(xy)^2[/tex]
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Summarizing:
(3+xz)(-3+xz)
[tex](y^2-xy)(y^2+xy)[/tex]
