Answered

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y = x² +1,x>0
find the inverse

Sagot :

absor201

Answer:

The inverse of x² +1 is:  

[tex]\sqrt{x-1},\:-\sqrt{x-1}[/tex]

Step-by-step explanation:

Given

y = x² + 1,  x>0

We know that A function g is the inverse of a function f if for y = f(x), x = g(y)

y = x² +1

Replace x with y

x = y² + 1

solve for y

y² = x - 1

Taking square root

[tex]y=\:\sqrt{x-1},-\sqrt{x-1}[/tex]

Thus, the inverse of x² +1 is:  

[tex]\sqrt{x-1},\:-\sqrt{x-1}[/tex]

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