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Sagot :
Answer:
question 19
(2x-5)(3x+1)
Step-by-step explanation:
question 19
6x^2-13x-5
6x^2 coefficient = 6
-13x coeddicient = -13
-5 is constant
multiply coefficient of first term by the constant
i.e. 6*-5= -30
get 2 factors of -30 whoose sum equals -13
-15 +2 = -13
rewrite to have
6x^2-15x+2x-5
3x(2x-5) the firs term
1(2x-5)
add up,
(3x+1)(2x-5)
Answer:
17)x=12, -7
18)x=+2, -2
19)(2x-5)(3x+1)
20)3(5x+4)(x-2)
Step-by-step explanation:
17) (x-12)(x+7)=0
x=12, -7
18)3x^2-12=0
3x^2=12
x^2=4
x=+2, -2
19)(ax+b)(cx+d)
Ax^2+Bx+C
A=6, B=-13, C=-5
ac=6
ad+bc=-13
bd=-5
a=2
b=-5
c=3
d=1
(2x-5)(3x+1)
20)3(5x^2-6x-8)
=3(5x+4)(x-2)
Hope I helped! And also, is this really college math? I'm in middle school and I know how to do it!
Can you give me brainliest, since I did all of them?
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