Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

16x^2 + 10x — 27 = -6x + 5

What are the solutions to this equation?


Sagot :

Answer:

x=1 or x=−2

Step-by-step explanation:

16x2+10x−27=−6x+5

Step 1: Subtract -6x+5 from both sides.

16x2+10x−27−(−6x+5)=−6x+5−(−6x+5)

16x2+16x−32=0

Step 2: Factor left side of equation.

16(x−1)(x+2)=0

Step 3: Set factors equal to 0.

x−1=0 or x+2=0

x=1 or x=−2

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.