Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

16x^2 + 10x — 27 = -6x + 5

What are the solutions to this equation?

Sagot :

Yashahim3

Answer:

x=1 or x=−2

Step-by-step explanation:

16x2+10x−27=−6x+5

Step 1: Subtract -6x+5 from both sides.

16x2+10x−27−(−6x+5)=−6x+5−(−6x+5)

16x2+16x−32=0

Step 2: Factor left side of equation.

16(x−1)(x+2)=0

Step 3: Set factors equal to 0.

x−1=0 or x+2=0

x=1 or x=−2

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.