Skyforclouds
Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

If a balloon containing 3000 L of gas at 39°C and 99 kPa rises to an altitude where the pressure is 45.5 kPa and the temperature is 16°C,
the volume of the balloon under these new conditions would be calculated using the following conversion factor ratios:

( the one I have marked, I’m not sure if that’s the answer or not )

If A Balloon Containing 3000 L Of Gas At 39C And 99 KPa Rises To An Altitude Where The Pressure Is 455 KPa And The Temperature Is 16C The Volume Of The Balloon class=

Sagot :

ardni313

[tex]\tt =3000~L\times \dfrac{289}{312}\times \dfrac{99}{45.5}[/tex]

Further explanation

Given

3000 L of gas at 39°C and 99 kPa to 45.5 kPa and 16°C,

Required

the new volume

Solution

Combined with Boyle's law and Gay Lussac's law  

[tex]\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}[/tex]

T₁ = 39 + 273 = 312

T₂ = 16 + 273 = 289

Input the value :

V₂ = (P₁V₁.T₂)/(P₂.T₁)

V₂ = (99 x 3000 x 289)/(45.5 x 312)

or we can write it as:

V₂ = 3000 L x (289/312) x (99/45.5)

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.