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Larry is collecting one coin each year from 1952 to 2000. If Larry has collected 40% of the coins, how many does he have left to collect?

Sagot :

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Answer:

29 coins

Step-by-step explanation:

Larry needs to collect [tex]60\%[/tex] of the coins still [tex]0.6[/tex]. [tex]2000-1952=48(+1)[/tex] because you're including 1952 [tex]=49[/tex]. [tex]49×0.6=29.4≈49[/tex].

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