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What is the equation of a line, in general form, that passes through point (1,-2) and has a siope of 1/3?

Sagot :

sqdancefan

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Answer:

  x -3y -7 = 0

Step-by-step explanation:

The general form of the equation for a line is ...

  ax +by +c = 0

where a, b, c are mutually prime and the leading coefficient is greater than zero.

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The general form equation for a line with slope m = rise/run through point (h, k) can be found by simplifying ...

  rise(x -h) -run(y -k) = 0 . . . . where run has the sign of the slope

For the given point and slope, we have ...

  1(x -1) -3(y -(-2)) = 0

  x -3y -7 = 0

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