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N2 + 3H2 → 2NH3


How many moles of NH3 could you make with 4.2021 g of N2?



I need this like rn pls .


Sagot :

Moles of NH3 = 0.3 moles

Further explanation

Given

N2 + 3H2 → 2NH3

4.2021 g of N2

Required

moles of NH3

Solution

mol N2 :

= 4.2021 g : 28 g/mol

= 0.15

From the equation, mol NH3 :

= 2/1 x mol N2

= 2/1 x 0.15

= 0.3 moles