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A solution is prepared by dissolving 25.0 mL ethanol, CH3CH2OH (d=0.789 g/mL), in enough water to produce 250.0 mL solution. What is the molarity of ethanol in the solution?

Sagot :

ardni313

The molarity = 1.716 M

Further explanation

Given

25 ml ethanol

d = 0.789 g/ml

250 ml solution

Required

The molarity

Solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]

mass of ethanol :

= 25 ml x 0.789 g/ml

= 19.725 g

mol ethanol :

= 19.725 g : 46 g/mol

= 0.429

The molarity :

= 0.429 : 0.25 L

= 1.716 M

abidemiokin

The molarity of ethanol in the solution is 1.716M

What is the molarity of a solution?

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

Determine the mass of ethanol :

Mass of ethanol = 25 ml x 0.789 g/ml

Mass of ethanol = 19.725 g

Determine the moles of ethanol

Moles = Mass/Molar mass

Moles = 19.725 g/46 g/mol

Moles of ethanol = 0.429moles

Calculate the molarity using the formula below;

Molarity = Moles/Volume

Molarity = 0.429/0.25 L

Molarity = 1.716 M

Hence the molarity of ethanol in the solution is 1.716M

Learn more on molarity here: https://brainly.com/question/17138838

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