Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A professor of cognitive psychology is interested in the percent accuracy on this memory encoding task among college students. She measures the percent accuracy for 64 randomly selected students. The professor knows that the distribution of scores is normal, but she does not know that the true average percent accuracy on this memory encoding task among college students is 0.794 percent correct with a standard deviation of 0.1110 percent correct.
The expected value of the mean of the 64 randomly selected students, M, is ______ mean and/or standard deviation just given to calculate the expected value of M.) . (Hint: Use the population
The standard error of M is_______ (Hint: Use the population mean and/or standard deviation just given to calculate the standard error.)

Sagot :

fichoh

Answer:

Mean of M = 0.794

Standard Error = 0.013875

Step-by-step explanation:

Given that :

Sample size, n = 64

Mean percentage accuracy, μ = 0.794

Standard deviation, σ = 0.1110

Since the distribution of scores is normal ;

Sample mean, m ~ μ

Hence, m ~ 0.794

The sample sta dard deviation of standard error ~ σ/sqrt(n)

Standard Error = 0.1110 / sqrt(64)

Standard Error = 0.1110 / 8

Standard Error = 0.013875

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.