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Although the vocal tract is quite complicated, we can make a simple model of it as an open-closed tube extending from the opening of the mouth to the diaphragm, the large muscle separating the abdomen and the chest cavity. What is the length of this tube if its fundamental frequency equals a typical speech frequency of 230 Hz? Assume a sound speed of 350 m/s.

Sagot :

samuelonum1

Answer:

0.76m

Explanation:

Given data

Frequency= 230Hz

speed= 350m/s

Since we are told that the frequency is the fundamental frequency n= 1

For a standing wave

Fn= nv/2L

n= 1

230= 1*350/2*L

230= 350/2L

cross multiply

2L= 350/230

2L=1.521

L=1.521/2

L=0.76m

Hence the length is 0.76m

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