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Sagot :
Answer/Step-by-step explanation:
AC = 1.2
AB = 4
BC = 2.6
DF = 3
DE = 10
EF = 6.5
Thus:
[tex] \frac{DE}{AB} = \frac{10}{4} = \frac{5}{2} [/tex]
[tex] \frac{DF}{AC} = \frac{3}{1.2} = \frac{3*10}{1.2*10} = \frac{30}{12} = \frac{5}{2} [/tex]
[tex] \frac{EF}{BC} = \frac{6.5}{2.6} = \frac{6.5*10}{2.6*10} = \frac{65}{26} = \frac{5}{2} [/tex]
The ratio of their corresponding sides are all equal to ⁵/2. Therefore, both triangles are similar.
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