Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer:
Please see the explanation below for proof
Step-by-step explanation:
Probability of choosing black ball from the bag
[tex]\frac{b}{b+r}[/tex]
Probability of choosing red ball from the bag
[tex]\frac{r}{b+r}[/tex]
After the addition of c balls of correspondent color –
P (R2/B1) [tex]= \frac{r}{(r+b+c)}[/tex]
P (R2/B2) [tex]=\frac{r+c}{(r+b+c)}[/tex]
B1 and B2 are mutually exclusive event
P (B1/R2) = [tex]\frac{\frac{r}{(r+b+c)} *\frac{b}{b+r}}{\frac{r}{(r+b+c)}*\frac{b}{b+r} + \frac{r+c}{(r+b+c)}* \frac{b}{b+r}}[/tex]
P (B1/R2) [tex]=\frac{b}{(r+b+c)}[/tex]
Hence, Proved
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.