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Sagot :
Given:
The equation is
[tex]20y-10x+5[/tex]
To find:
The slope intercept form of the given equation.
Solution:
The slope intercept form of a linear equation is
[tex]y=mx+b[/tex]
Where, m is slope and b is the y-intercept.
We have,
[tex]20y-10x=5[/tex]
We need to isolate y. Add 10x on both sides.
[tex]20y-10x+10x=5+10x[/tex]
[tex]20y=5+10x[/tex]
Divide both sides by 20.
[tex]\dfrac{20y}{20}=\dfrac{5+10x}{20}[/tex]
[tex]y=\dfrac{5}{20}+\dfrac{10x}{20}[/tex]
[tex]y=\dfrac{1}{4}+\dfrac{x}{2}[/tex]
[tex]y=\dfrac{1}{2}x+\dfrac{1}{4}[/tex]
Therefore, the slope intercept form of the given equation is [tex]y=\dfrac{1}{2}x+\dfrac{1}{4}[/tex].
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