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20y-10x=5 in slope intercept form can you explain the steps

Sagot :

Given:

The equation is

[tex]20y-10x+5[/tex]

To find:

The slope intercept form of the given equation.

Solution:

The slope intercept form of a linear equation is

[tex]y=mx+b[/tex]

Where, m is slope and b is the y-intercept.

We have,

[tex]20y-10x=5[/tex]

We need to isolate y. Add 10x on both sides.

[tex]20y-10x+10x=5+10x[/tex]

[tex]20y=5+10x[/tex]

Divide both sides by 20.

[tex]\dfrac{20y}{20}=\dfrac{5+10x}{20}[/tex]

[tex]y=\dfrac{5}{20}+\dfrac{10x}{20}[/tex]

[tex]y=\dfrac{1}{4}+\dfrac{x}{2}[/tex]

[tex]y=\dfrac{1}{2}x+\dfrac{1}{4}[/tex]

Therefore, the slope intercept form of the given equation is [tex]y=\dfrac{1}{2}x+\dfrac{1}{4}[/tex].

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