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Sagot :
Answer:
Explanation:
When calcium hydroxide is dissolved in water , it ionizes as follows .
Ca( OH)₂ = Ca⁺² + 2 OH ⁻
When it is dissolved in water which contains minimal OH⁻ , so there is almost no common ion effect . Hence calcium hydroxide is fully dissolved in pure water solvent .
When 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.500 M sodium hydroxide solution in beaker , it is not fully dissolved due to common ion of hydroxide ion ( OH⁻ )
NaOH = Na⁺ + OH⁻
OH⁻ ion from NaOH , suppresses the dissolution of calcium hydroxide .
Similarly
When A 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.200 M sodium hydroxide solution in beaker , it is not fully dissolved due to common ion of hydroxide ion ( OH⁻ )
NaOH = Na⁺ + OH⁻
OH⁻ ion from NaOH , suppresses the dissolution of calcium hydroxide
When 1.00 mole sample of solid calcium hydroxide is added to 500.0 mL of 0.200 M calcium nitrate solution , it is not fully dissolved due to common ion of calcium ion ( Ca⁺² )
Ca( NO₃)₂ = Ca⁺² + 2NO₃⁻
Ca⁺² ion from Ca( NO₃)₂ , suppresses the dissolution of calcium hydroxide .
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