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ou are a work study for the chemistry department. Your supervisor has just asked you to prepare 500 mL of 3 M HCl for tomorrow’s undergraduate experiment. In the stockroom explorer, you will find a cabinet called "stock solutions". Open this cabinet to find a 2.5 L bottled labeled "11.6 M HCl". The concentration of the HCl is 11.6 M. Please prepare a flask

Sagot :

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Answer:

Add to a 500mL volumetric flask 300mL of water, the 129mL of the 11.6M HCl solution and then complete to volume with water

Explanation:

To make 500mL = 0.500L of a 3M HCl from the 11.6M HCl stock we need first to find the moles of HCl we need:

Moles HCl:

0.500L * (3mol / L) = 1.5 moles of HCl are needed

These moles are obtained from the 11.6M HCl solution. The volume required is:

1.5mol * (1L / 11.6moles HCl) = 0.129L = 129mL must be added to the solution.

That means to prepare the 500mL of the 3M HCl you need to:

Add to a 500mL volumetric flask 300mL of water, the 129mL of the 11.6M HCl solution and then complete to volume with water

Answer:

Calculation: 11.6 M × V = 3.0 M × 0.500 liters

V = 0.13 liters

Steps for dilution:

Measure out 0.13 liters of the concentrated solution of 11.6 M HCl using a volumetric pipet.

Transfer this into solution into a 500 milliliter volumetric flask.

Add water to the flask until it reaches a total volume of 500 milliliters.

Solution: V = 0.13 liters

Explanation:

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