Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m. Based on past experience the company has determined that the employee is equally likely to arrive at any time between 8:00 a.m. and 8:30 a.m. Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m. Round your answer to four decimal places, if necessary.

Sagot :

Answer:

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.

We can consider 8 am = 0, and 8:30 am  = 30, so [tex]a = 0, b = 30[/tex]

Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.

Between 15 and 25, so:

[tex]P(15 \leq X \leq 25) = \frac{25 - 15}{30 - 0} = 0.3333[/tex]

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.