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Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.02 g/mL. Only enter the numerical value with 3 significant figures in the answer box below. Do NOT type in the unit (m).

Sagot :

maacastrobr

Answer:

2.03

Explanation:

Let's assume we have 1 L of the solution:

  • There would be 2.07 ethylene glycol moles.
  • The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can calculate the molality:

  • molality = moles of solute / kg of solvent
  • molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

mahima6824soni

The molality of an ethylene glycol solution is 2.03 kg.

What is molality?

The moles of solute divided by the mass of solvent in kilograms is known as the molality of a solution.

Calculation of molality:

Given that, molarity is 2.07 M

Density is 1.02 g/ml

Step 1: To convert  the litre into grams, multiply the quantity by 1000

The weight of the solution is [tex]\bold{1.02 \;g/ml\; \times 1000 = 1020 g}[/tex]

Now, molality = moles of solute is divided by mass of solvent in kilograms.

[tex]\bold{Molality = 2.07 \times \dfrac{1020}{1000} = 2.03\; kg}[/tex]

Thus, the molality of the solution is 2.03 kg

Learn more about molality, here:

https://brainly.com/question/4580605

   molality = moles of solute / kg of solvent

   molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

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