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A 1-kg plastic block is neutrally buoyant when submerged in water with a density of 1 g/cm3. If the same block is placed, such that it is completely submerged, in a container of oil with a density of 0.8 g/cm3, find the acceleration of the block.

Sagot :

Answer:

-2 m/s

Explanation:

The computation of the acceleration of the block is as follows:

The volume of the block is

V = 1kg ÷ 1,000 kg/m^3 = 1 ÷ 1,000 m^3

Now at the time of submerging in the oil

Net force is

[tex]m_g - F_B = m \times (-a)\\\\m_g - v\times S_{oil} \times g = -ma\\\\a = (\frac{v}{m} \times S_{oil} - 1) g\\\\= (\frac{1}{1000} \times 0.8 \times 1000 -1 ) \times 10\\\\[/tex]

= -2 m/s

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