Answered

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Simplify p^-8/7^-2q^-9

Sagot :

LanceLongFei

Answer:

[tex]\frac{7^2}{p^8 \cdot q^9}[/tex]

Step-by-step explanation:

[tex]\frac{p^{-8}}{7^{-2}} \cdot q^{-9} = \frac{\frac{1}{p^8}}{\frac{1}{7^2}} \cdot \frac{1}{q^9} = \frac{7^2}{p^8 \cdot q^9}[/tex] by the definition of negative exponents: [tex]a^{-b} = \frac{1}{a^b}[/tex] for all [tex]a,b[/tex] so long as [tex]a\ne 0[/tex].

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