Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The entry tickets at a community fair cost $5 for children and $10 for adults. On a certain day 1000 people entered in the fair and $7,100 is collected. How many adults and how many children were at the fair?

Sagot :

Lanuel

Answer:

C = 580 children.

A = 420 adult.

Step-by-step explanation:

Let the number of children be C.

Let the number of adult be A.

Translating the word problem into an algebraic equation, we have;

A + C = 1000  .......equation 1

10A + 5C = 7100  .......equation 2

A = 1000 - C .......equation 3

Substituting eqn 3 into eqn 2, we have;

10(1000 - C) + 5C = 7100

10000 - 10C + 5C = 7100

10000 - 7100 = 10C - 5C

2900 = 5C

C = 2900/5

C = 580 children.

Now, to find the value of A.

From equation 3;

A = 1000 - C

A = 1000 - 580

A = 420 adult.

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.