Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

If 1.2 g of ammonium bicarbonate is treated with .75 grams of sodium chloride, 63.0075 grams sodium bicarbonate will be produced. In this reaction NaCI is limiting reagent. True or false

Sagot :

Answer:

True

Explanation:

Limiting reagent is the reactant that determines the progress of the reaction. It determines how much of the product is formed.

The equation for this reaction is;

NaCl (aq) + NH4HCO3 (aq) → NaHCO3 (aq) + NH4Cl (aq)

From the reaction, 1 mol of NaCl reacts with 1 mol of NH4HCO3 to produce 1 mol of NaHCO3

Converting to masses using; Mass = Number of moles * Molar mass

58.44g of NaCl reacts with 79.056g of NH4HCO3

If we were to  sue the whole 1.2 g of NH4HCO3 we would require xg of NaCl

58.44 = 79.056

x = 1.2

x = 0.887g

The fact that 1.2g of NH4HCO3 requires 0.887g of NaCl (which is less than the available 0.75g) means that NaCl is the limiting reagent.

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.