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8x² + 16x - 62 = -5, solve by completing the square. PLEASE HELP IVE BEEN STRUGGLING FOR HOURS

Sagot :

Answer:

x=-1+[tex]\frac{1}{4}[/tex][tex]\sqrt{130\\}[/tex] or x=-1+[tex]\frac{-1}{4}[/tex][tex]\sqrt{130}[/tex]

Step by step:

Step 1: Subtract -5 from both sides.

8x2+16x−62−(−5)=−5−(−5)

8x2+16x−57=0

For this equation: a=8, b=16, c=-57

8x2+16x+−57=0

(plus-minus) = ±

Step 2: Use quadratic formula with a=8, b=16, c=-57.

x=[tex]\frac{-b(plus-minus)\sqrt{x} b^2-4ac}{2a}[/tex]

x=[tex]\frac{-(16)(plus-minus)\sqrt{(16)^2-4(8)(-57)} }{2(8)}[/tex]

x=[tex]\frac{-16(plus-minus) \sqrt{2080} }{16}[/tex]

ANSWER:

x=-1+[tex]\frac{1}{4}[/tex][tex]\sqrt{130}[/tex] or x=-1+[tex]\frac{-1}{4}[/tex][tex]\sqrt{130}[/tex]

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