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A 8.15 g sample of hydrogen peroxide (H2O2) decomposes to form water and oxygen. The temperature and pressures conditions in the lab were 21.2oC and 761.4 torr, respectively. The oxygen gas is collected over a sample of water at 21.2oC; the vapor pressure of water at that temperature is 18.9 torr. When the water level inside and outside of the tube is equal the volume of gas is recorded as 176.23 mL. a) Write and balance the equation for the decomposition reaction

Sagot :

Answer: [tex]H_2O_2\rightarrow H_2+O_2[/tex]

Explanation:

Decomposition is a type of chemical reaction in which one reactant gives two or more than two products.

According to law of conservation of mass, mass can neither be created nor be destroyed. Thus the number of atoms of each element must be same on reactant and product side. Thus chemical equations are balanced.

The balanced equation for the decomposition reaction  of hydrogen peroxide is:

[tex]H_2O_2\rightarrow H_2+O_2[/tex]

Decomposition is a type of chemical reaction in which a chemical breaks into two or more molecules or atoms. One reactant breaks into two products which can be shown as:

                                         XY----->X + Y

The decomposition reaction of hydrogen peroxide can be written as:

                                           

                                              [tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]

  • According to the mass conserving law the mass can neither be added nor deleted they can just get transferred.

  • For a reaction to be stable the number of atoms on both sides of the reaction should be balanced.

Therefore, the balanced chemical reaction of decomposition of hydrogen peroxide will be:

                                             [tex]H_{2}O_{2} = H_{2} + O_{2}[/tex]

To learn more about decomposition reaction follow the given link:

https://brainly.com/question/8009068