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A mixture of cyclopropane (C3H6) and oxygen (O2) is sometimes used as a general anesthetic. In a mixture, the partial pressures of cyclopropane and oxygen are 170. torr and 570. torr, respectively. Calculate the ratio of the moles of oxygen to the moles of cyclopropane in the mixture.

Sagot :

Answer:

0.30

Explanation:

Provided that the volume and pressure remains constant

[(Pressure of cyclopropane)/ (Pressure of Oxygen)] = [(no. Of moles of cyclopropane)/(no. Of moles of Oxygen)]

Pressure of cyclopropane= 170. torr

Pressure of Oxygen= 570. torr

If we substitute the values

[(no. Of moles of cyclopropane)/(no. Of moles of Oxygen)] = 170/570

[(no. Of moles of cyclopropane)/(no. Of moles of Oxygen)] = 0.30

Hence, the ratio of the moles of oxygen to the moles of cyclopropane in the mixture is 0.30