Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Answer:
0.2690 kg
Step-by-step explanation:
Given that:
For cutting a 4.5 kg block of cheese; the standard deviation:
[tex]S_x = 0.1 \ kg[/tex]
For a large no of blocks, at 95% confidence level;
Using the t table; where the degree of freedom is infinity or > 30
t-distribution (t) = 2
∴
[tex]P_x = tS_x[/tex]
[tex]P_x = 2 \times 0.1[/tex]
[tex]P_x = 0.2 \ kg[/tex]
The system uncertainty as a result of the accuracy [tex]B_x[/tex] is:
[tex]B_x = 1.5\% \ of \ reading[/tex]
[tex]B_x = (\dfrac{1.5}{100})(12 kg)[/tex]
[tex]B_x = 0.18 \ kg[/tex]
The total uncertainty for a single experiment with a 95% confidence interval will be:
[tex]w_s = ( B_x^2 + P_x^2)^{\frac{1}{2}[/tex]
[tex]w_s = (0.18^2 + 0.2^2)^{\frac{1}{2}[/tex]
[tex]\mathbf{w_s = 0.2690 \ kg}[/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.