Answer:
5.13 g of CO₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
C₁₂H₂₂O + 17O₂ —> 12CO₂ + 11H₂O
Next, we shall determine the mass of C₁₂H₂₂O that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:
Molar mass of C₁₂H₂₂O = 182 g/mol.
Mass of C₁₂H₂₂O from the balanced equation = 1 × 182 = 182 g
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Mass of CO₂ from the balanced equation = 12 × 44 = 528 g
SUMMARY:
From the balanced equation above,
182 g of C₁₂H₂₂O reacted to produce 528 g of CO₂.
Finally, we shall determine the mass of CO₂ produced from the reaction. This can be obtained as follow:
From the balanced equation above,
182 g of C₁₂H₂₂O reacted to produce 528 g of CO₂.
Therefore, 1.77 g of C₁₂H₂₂O will react to produce = (1.77 × 528)/182 = 5.13 g of CO₂.
Thus, 5.13 g of CO₂ were obtained from the reaction.
