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How much time does it take for a spinning baseball with an angular speed of 38 rad/s to rotate through 15 degrees

Sagot :

onyebuchinnaji

Answer:

the time of motion of the ball is 6.89 ms.

Explanation:

Given;

angular speed, ω = 38 rad/s

angular distance, θ = 15 degrees

Angular distance in radian;

[tex]\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad[/tex]

Time of motion is calculated as;

[tex]time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms[/tex]

Therefore, the time of motion of the ball is 6.89 ms.

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