Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

In the year 2054 the government estimates that out of every 1,000,100 citizens 1,000,000 will remain law-abiding, and 100 will eventually commit a crime. The government is deciding whether to rely on the clairvoyant Precogs to stop the criminals before they commit the crime. If a person is going to commit a crime, the Precogs identify that person correctly 99.999% of the time (in other words, the Precogs fail to predict crime only in 0.001% of the cases). If a person is not going to commit a crime, the Precogs identify that person as law-abiding 99.99% of the times (in other words, the Precogs convict innocent people only in 0.01% of the cases). What is the probability that a person flagged as a future criminal by the Precogs will actually commit a crime

Sagot :

Answer:

0.9091 = 90.91% probability that a person flagged as a future criminal by the Precogs will actually commit a crime

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)}[/tex]

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Flagged as future criminal

Event B: Commits a crime.

In the year 2054 the government estimates that out of every 1,000,100 citizens 1,000,000 will remain law-abiding, and 100 will eventually commit a crime.

This means that [tex]P(B) = \frac{100}{1000100} = 0.00009999[/tex]

If a person is going to commit a crime, the Precogs identify that person correctly 99.999% of the time

This means that [tex]P(A|B) = 0.99999[/tex]

Probability of being identified as a criminal:

0.99999 out of 0.00009999(identified and commits crime).

(1-0.99999) out of (1-0.00009999) (identifed and does not commits crime). So

[tex]P(A) = 0.99999*0.00009999 + (1-0.99999)*(1-0.00009999) = 0.000109988[/tex]

What is the probability that a person flagged as a future criminal by the Precogs will actually commit a crime

[tex]P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.00009999*0.99999}{0.000109988} = 0.9091[/tex]

0.9091 = 90.91% probability that a person flagged as a future criminal by the Precogs will actually commit a crime