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Problem 6: A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.3 × 105 m/s2 for 8.2 × 10-4 s.Ball,removedc795646bb4371e1754411a7dadf94458c503446af1b6450bb3269c1f97e8ef53removedremoved58b1e9a401041b69266daacea519e828d050d14013adc67f8c64697e40f2ef89removedtheexpertta - tracking id: 0W86-2A-6A-4E-962A-28979. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account.show answer No Attempt What is the gun’s muzzle velocity (that is, the bullet’s final speed), in meters per second

Sagot :

Answer:

v = 5.166 10² m / s

Explanation:

We can solve this exercise using the kinematics equations

           v = v₀ + at

as the bullet starts from rest its initial velocity is zero

           v = a t

let's calculate

           v = 6.3 10⁵   8.2 10⁻⁴

           v = 5.166 10² m / s

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