Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Find the angle between the given vectors to the nearest tenth of a degree.


u = 6, -1, v = 7, -4

20.3°
10.2°
0.2°
30.3°

Sagot :

Answer:

20.3

Step-by-step explanation:

Answer:

Step-by-step explanation:

u=6i-j

v=7i-4j

u.v=|6i-j||7i-4j| cos α,where α is the angle between u & v.

(6i-j).(7i-4j)=√(6²+(-1)²)√(7²+(-4)²) cos α

(6)(7)+(-1)(-4)=√37√65 cos α

42+4=√37√65  cos α

[tex]\cos \alpha =\frac{46}{\sqrt{37} \sqrt{65} } \\\alpha =\cos^{-1}\frac{46}{\sqrt{37} \sqrt{65} } \approx 20.28^\circ \approx 20.3^\circ[/tex]