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Sagot :
Answer:
13.22 L
Explanation:
Given data:
Volume of ammonia = ?
Mass of ammonia = 10.0 g
Temperature = standard = 273.15 K
Pressure = standard = standard = 1 atm
Solution:
First of all we will calculate the number of moles of ammonia.
Number of moles = mass/molar mass
Number of moles = 10.0 g/ 17 g/mol
Number of moles = 0.59 mol
one mole of any substance at standard temperature and pressure occupy 22.41 L . Thus, 0.59 moles of ammonia will occupy,
0.59 mol × 22.4 L / 1 mol
13.22 L
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