Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
Step-by-step explanation:
From the given information:
Let A be the event where an item is identified as defective;
B₁ to be the event where an item is actually defective
B₂ to be the event that the item is good
So;
P(B₁) = 0.009
P(B₂) = 0.991
Probability that an item is classified as defective when it is actually defective is P(A|B₁) = 0.99
Probability that an item is classified as defective when it is actually good is P(A|B₂) = 0.005
∴
Probability of classifying a product as defective = P(A)
P(A) = P(A|B₁) × P(B₁) + P(A|B₂) × P(B₂)
P(A) = 0.99 × 0.009 + 0.005 × 0.991
P(A) = 0.0139
P(A) = 1.39%
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.