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Sagot :
Answer:
Step-by-step explanation:
From the given information:
Let A be the event where an item is identified as defective;
B₁ to be the event where an item is actually defective
B₂ to be the event that the item is good
So;
P(B₁) = 0.009
P(B₂) = 0.991
Probability that an item is classified as defective when it is actually defective is P(A|B₁) = 0.99
Probability that an item is classified as defective when it is actually good is P(A|B₂) = 0.005
∴
Probability of classifying a product as defective = P(A)
P(A) = P(A|B₁) × P(B₁) + P(A|B₂) × P(B₂)
P(A) = 0.99 × 0.009 + 0.005 × 0.991
P(A) = 0.0139
P(A) = 1.39%
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