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Sagot :
Answer:
88%
Explanation:
Step 1: Write the balanced equation
C₆H₁₁OH ⇒ C₆H₁₀ + H₂O
Step 2: Calculate the moles corresponding to 4.1 g of C₆H₁₁OH
The molar mass of C₆H₁₁OH is 100.16 g/mol.
4.1 g × 1 mol/100.16 g = 0.041 mol
Step 3: Calculate the theoretical yield, in moles, of C₆H₁₀
The molar ratio of C₆H₁₁OH to C₆H₁₀ is 1:1. The theoretical yield of C₆H₁₀, in moles, is 1/1 × 0.041 mol = 0.041 mol.
Step 4: Calculate the mass corresponding to 0.041 moles of C₆H₁₀
The molar mass of C₆H₁₀ is 82.14 g/mol.
0.041 mol × 82.14 g/mol = 3.4 g
Step 5: Calculate the percent yield of C₆H₁₀
We will use the following expression.
percent yield = experimental yield/theoretical yield × 100%
percent yield = 3.0 g/3.4 g × 100% = 88%
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