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Iron has a specific heat of o.45 J/g °C. Removing -1.16 E 2 J of energy lowered the temperature of iron from 89 °C to 26.41 °C. What was the mass of the iron?

Iron Has A Specific Heat Of O45 Jg C Removing 116 E 2 J Of Energy Lowered The Temperature Of Iron From 89 C To 2641 C What Was The Mass Of The Iron class=

Sagot :

Answer:

m = 4.11 grams

Explanation:

Given that,

The specific heat of Iron, c = 0.45 J/g°C

Heat removed, [tex]Q=1.16\times 10^2\ J[/tex]

Initial temperature, [tex]T_i=89^{\circ} C[/tex]

Final temperature, [tex]T_f=26.41^{\circ} C[/tex]

We need to find the mass of the iron. We know that the heat removed in terms of specific heat is given by :

[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{-1.16\times 10^2}{0.45\times (26.41-89)}\\\\m=4.11\ g[/tex]

So, the mass of the iron is 4.11 grams.

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