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Sagot :
Answer:
That is there is maximum profit when 250 units of $250 model computer and 50 units of $400 model computer is stocked.
Explanation:
Let x represent the number of $250 model and let y represent the number of $400 model. Since the total monthly demand will not exceed 250 units, hence:
x + y < 250 (1)
Also the merchant does not want to invest more than $70,000, hence:
250x + 400y < 70000 (2)
x, y ≥ 0
Plotting the equations using geogebra online graphing tool. The solution to the problem is at (0,0), (200, 50), (250,0), (0, 175).
The profit equation is:
Profit = 45x + 50y
At (0,0); Profit = 45(0) + 50(0) = 0
At (250,0); Profit = 45(250) + 50(0) = $11250
At (0,175); Profit = 45(0) + 50(175) = 8750
At (200,50); Profit = 45(200) + 50(50) = $11500
Therefore the maximum profit is at (200, 50). That is there is maximum profit when 250 units of $250 model computer and 50 units of $400 model computer is stocked.
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