Answered

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Cuantos gramos de nitrato de potasio (KNO3) son necesarias para preparar 800ml de solucion al 12 % m/v

Sagot :

Answer:

96 g

Explanation:

Tomando en cuenta que estamos hablando de una solución de Nitrato de potasio cuya concentración es 12% m/V, debemos entonces usar la expresión de %m/V:

%m/V = msto / Vsol * 100   (1)

De esta expresión, debemos despejar la masa de soluto (msto) que es precisamente el valor que estamos buscando. Al hacer el despeje tenemos:

msto = %m/V * Vsol / 100    (2)

Ahora solo nos queda sustituir los valores dados y resolver:

msto = 12 * 800 / 100

msto = 96 g de KNO₃

Espero te sirva.

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