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An 240. mL sample of oxygen at 90.00C and was cooled at constant pressure
until it has a volume of 450.0 mL. What was the final Celsius temperature of this
gas? *


Sagot :

The final temperature : T₂ = 680.625 K

Further explanation

Given

V₁=240 ml

T₁ = 90 + 273 = 363 K

V₂ = 450 ml

Required

The final temperature

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

Input the value :

T₂ = V₂T₁/V₁

T₂ = 450 x 363 / 240

T₂ = 680.625 K