Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
The equilibrium concentrations of HF = 0.058 , F2 = 0.006M , HClO =0.16M , and ClO2 = 7.7 × 10⁻⁷M.
Explanation:
The Ka values for HClO₃ and HF are given as 2.9 × 10⁻⁸ and 6.6 × 10⁻⁴ respectively. The molar concentration for HF = 0.23/ 3.60L = 0.064 M and 0.57/ 3.60 = 0.16 M.
When HF is reacted with water, it ionizes to form H₃O⁺ and F⁻. The concentration of H₃O⁺ and F⁻ can be calculated below:
HF(aq) <------------------------> H30^+ + F^-.
Ka = [H^+] [F^-]/[HF] .
6.6× 10^-4 = [x][x]/ ( 0.064- x).
x = 0.0060 M.
The concentration of H₃O⁺ and F⁻ = 0.0060 M respectively.
The pH = - log [ H₃O⁺ ] = -log [0.0060] = 2.22.
When HClO is reacted with water, it ionizes to form H₃O⁺ and F⁻. The concentration of H₃O⁺ and ClO⁻ can be calculated below:
HClO(aq) <------------------------> H30^+ + ClO^-.
Ka = [H^+] [ClO^-]/[HClO] .
6.6× 10^-4 = [0.006 + x] [x]/ ( 0.16 - x).
x = 7.7 × 10^-7M.
[ClO^-] = 7.7 × 10^-7 M.
[HClO] = 0.16 - 7.7 × 10^-7 = 0.16M.
[F^-] = 0.006 M.
[HF] = 0.064 - 0.006 = 0.058 M.
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.