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Sagot :
Answer:
[tex]n = \frac{1300}{5.50}[/tex]
[tex]n = 236[/tex]
Step-by-step explanation:
Given
The cost of printing one calendars [tex]= 5.5[/tex] dollars
The one time charge of taking photo [tex]= 200[/tex] dollars
The total sum of money with the club [tex]= 1500[/tex] dollars
The total sum of money going into printing of calendars [tex]= 1500 -200 = 1300[/tex] dollars
The total number of calendars that can be printed with remaining [tex]1300[/tex] dollars is equal to
[tex]n = \frac{1300}{5.50}[/tex]
[tex]n = 236[/tex]
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