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A tortoise and hare start from rest and have a race. As the race begins, both accelerate forward. The hare accelerates uniformly at a rate of 1 m/s2 for 4 seconds. It then continues at a constant speed for 12.9 seconds, before getting tired and slowing down with constant acceleration coming to rest 66 meters from where it started. The tortoise accelerates uniformly for the entire distance, finally catching the hare just as the hare comes to a stop. 1)How fast is the hare going 1.6 seconds after it starts

Sagot :

Answer:

v = 4 m/s

Explanation:

Given that,

Initial speed of hare, u = 0

The hare accelerates uniformly at a rate of 1 m/s² for 4 seconds.

We need to find how fast is the hare going 1.6 seconds after it starts. Let the speed be v. So,

v = u+at

Substitute all the values,

v = 0+1×4

v = 4 m/s

So, the required speed of the hare is 4 m/s after it starts.

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