Answer: 0.800 M
Basically, the ratio is 2:1, so when you have 1 M of Li2HPO4 it means you have 2 M in the concentration of lithium ions. So knowing the ratio, we know we just need to multiply 0.400 x 2.
I'm bad at explaining it, but got it right on chem101 sooo
The concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄ is 0.8 M.
The concentration of a substance is simply the amount of the substance in 1 L of water.
To obtain the concentration of lithium ion, Li⁺ in Li₂HPO₄, we'll begin by writing the dissociation equation of Li₂HPO₄. This is illustrated below:
From the balanced equation above,
1 mole of Li₂HPO₄ produced 2 moles of Li²⁺.
Finally, we shall determine the concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄. This can be obtained as follow:
From the balanced equation above,
1 mole of Li₂HPO₄ produced 2 mole of Li⁺.
Therefore, 0.4 M Li₂HPO₄ will produce = 2 × 0.4 = 0.8M Li²⁺
Thus, 0.8 M lithium ion, Li⁺ is present in the solution.
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