Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

An 80 N rightward force is applied to a 10 kg object to accelerate it to the right.
The object encounters a friction force of 50 N.

Sagot :

ardni313

net force = 30 N

mass = 8.16 kg

acceleration = 3.68 m/s²

Further explanation

Given

80 N force applied

mass of object = 10 kg

Friction force = 50 N

Required

Net force

mass

acceleration

Solution

  • net force

Net force = force applied(to the right) - friction force(to the left)

Net force = 80 - 50 = 30 N

  • mass

Gravitational force(downward) : F = mg

m = F : g

m = 80 : 9.8

m = 8.16 kg

  • acceleration

a = F net / m

a = 30 / 8.16

a = 3.68 m/s²

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.