Answer:
7.08 L
Explanation:
From the question given above, the following data were obtained:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.2 + 0.5 = 1.7 moles
Final volume (V₂) =?
From ideal gas equation,
PV = nRT
Divide both by n
PV / n = RT
Divide both side by P
V / n = RT/P
RT/P => constant
Therefore,
V₁ / n₁ = V₂ / n₂
With the above formula i.e
V₁/n₁ = V₂/n₂
We can obtain the final volume of the gas as follow:
Initial mole (n₁) = 1.2 moles
Initial volume (V₁) = 5 L
Final mole (n₂) = 1.7 moles
Final volume (V₂) =?
V₁/n₁ = V₂/n₂
5 / 1.2 = V₂ / 1.7
Cross multiply
5 × 1.7 = 1.2 × V₂
8.5 = 1.2 × V₂
Divide both side by 1.2
V₂ = 8.5 / 1.2
V₂ = 7.08 L
Therefore, the final volume of the gas is 7.08 L
