Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

there's 4.1*10^25 particles of calcium phosphate, how many grams of calcium phosphate is that

Sagot :

Mass of Calcium phosphate : = 21127.7 g

Further explanation

Given

4.1 x 10²⁵ particles of Calcium phosphate

Required

mass

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

mol Calcium phosphate :

n = N : No

n = 4.1 x 10²⁵ : 6.02 x 10²³

n = 68.11

mass Calcium phosphate Ca3(PO4)2 :

= mol x MW

= 68.11 x 310.2 g/mol

= 21127.7 g

= 21.13 kg

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.