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Sagot :
Answer:
we have the expression as;
1/sin u cos u
Step-by-step explanation:
tan u = sin u/cos u
cot u = cos u/sin u
Thus;
sin u/cos u + cos u/sin u
The lcm is sin u cos u
Thus, we have that;
(sin^2 u + cos^2 u)/sin u cos u
But ; sin^2 u + cos^2 u = 1
so we have ;
1/sin u cos u
The requested trigonometric expression in terms of sine and cosine is;
[tex]f(u) = \frac{1}{ \frac{sinu}{cosu} + \frac{cosu}{sinu} } [/tex]
Trigonometric expressions:
We must remember,
- tan u = sin(u)/cos(u)
- and cot u = cos(u)/sin(u).
Therefore we have;
sin(u)/cos(u) + cos(u)/sin(u) = 1/f(u)
By Cross-product; we have;
[tex]f(u) = \frac{1}{ \frac{sinu}{cosu} + \frac{cosu}{sinu} } [/tex]
Therefore, the required function, f(u) in terms of sin u and cos u is as represented above.
Read more on trigonometry;
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