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Find the value of x pls help thank u so much

Find The Value Of X Pls Help Thank U So Much class=

Sagot :

Answer:

7.81

Step-by-step explanation:

Answer:

[tex] \sqrt{66} [/tex]

Step-by-step explanation:

By geometric mean property:

[tex]BD = \sqrt{6 \times 5} = \sqrt{30} \\ \\ In \: \triangle ABD: \\ by \: pythagoras \: theorem : \\ \\ AD^2 = AB^2 + BD^2 \\ \\ {x}^{2} = {6}^{2} + {( \sqrt{30}) }^{2} \\ \\ {x}^{2} = 36 + 30 \\ \\ {x}^{2} = 66 \\ \\ x = \sqrt{66} [/tex]