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Write the equation of the perpendicular bisector of the segment AB.
A (1, 5) and B (7, -1)


Sagot :

Answer:

The equation of the perpendicular bisector of the segment AB is [tex]y = x - 2[/tex]

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

[tex]y = mx + b[/tex]

In which m is the slope and b is the y-intercept.

Perpendicular lines and slopes:

If two lines are perpendicular, the multiplication of their slopes is -1.

Equation of the perpendicular bisector of the segment AB.

Equation of a line that passes through the midpoint of segment AB and is perpendicular to AB.

Midpoint of segment AB:

Mean of their coordinates x and y. So

(1+7)/2 = 4

(5-1)/2 = 2

So (4,2).

Slope of segment AB:

When we have two points, the slope between them is given by the change in y divided by the change in x.

In segment AB, we have points (1,5) and (7,-1). So

Change in y: -1 - 5 = -6

Change in x: 7 - 1 = 6

Slope: -6/6 = -1

Equation of the perpendicular bisector:

The slope, multiplied with the slope of segment AB, is -1. So

[tex]-1m = -1[/tex]

[tex]m = 1[/tex]

So

[tex]y = x + b[/tex]

Passes through (4,2), which means that when [tex]x = 4, y = 2[/tex]. So

[tex]y = x + b[/tex]

[tex]2 = 4 + b[/tex]

[tex]b = -2[/tex]

So

[tex]y = x - 2[/tex]