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Suppose that a 4 × 4 matrix A has eigenvalues λ1 = 1, λ2 = − 3, λ3 = 5, and λ4 = − 5. Use the following method to find det (A).

If
p(λ) = det (λI − A) = λn + c1λn − 1 + ⋯ + cn

So, on setting λ = 0, we obtain that

det (− A) = cn or det (A) = (− 1)ncn

det (A) = ?

Sagot :

ifyg58guuhg98gy58u5j

Answer:

9y09

Step-by-step explanation:

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