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the pressure of 1 mol of gas is decreased to 0.05 atm 273.k. what happens to the molar volume of the gas under these conditions?

Sagot :

ardni313

The molar volume of the gas : V = 447.993 L

Further explanation

Given

n = 1 mol

P = 0.05 atm

T = 273 K

Required

The molar volume

Solution

Ideal gas law :

PV=nRT

V = nRT/P

Input the value :

V = 1 x 0.08205 x 273 / 0.05

V = 447.993 L

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